Conversion factor for 1s cotton counts

Conversion factor for 1^s cotton counts:

                     840   yds. Of cotton weighs   =       1 lb

                     840   m     "      "      weighs   = 453.6 ×1.093613298 gm     

                     9000 m     "      "      weighs   = 453.6×1.093613298 × (9000/840) gm                                                                                                   = 5315 gm

                                                                  or 5315

                                                (Equivalent denier or conversion factor)

Therefore, for 25^s, Denier (D) = 5315 / 25, that is, D = 5315 / C     

                                 50s         cotton count         = 5315/50 = 106.3 denier     

   2/50s                               cotton count     = 5315/25  = 212.6 denier

   106.3                               denier                = 5315/106.3       = 50s cotton count

                       So we can write, 5315/C=D.

                                       If 9000m of filament weigh 9 gms, meaning 9 denier

Then, mathematically,   1000m of filament will weigh 1 gram, also, 9 denier       

          Again we know,   if 1000m of filament weigh 1 gram, that is, 1 tex

So from the ‘linear mass density of fibers’ point of view:

                                            9 denier ≈ 1.0000 tex

                                            1 denier ≈ 0.1111 tex        

Mathematical value is higher for denier.

So any number of D (Denier) ≠ any number of T (Tex)

                      From above T   = D × 0.1111       

                                          or T   =  (5315 / C ) 0.1111 

                                         or T   =  590.5 / C    (as we know D = 5315 / C)        

                                         or TC = 590.5 = 591